(D) The hydrolysis of $methyl \ cyanide$ $(CH_3CN)$ in the presence of an alkali (like $NaOH$) proceeds through the formation of $acetamide$ $(CH_3CON

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(D) The hydrolysis of $methyl \ cyanide$ $(CH_3CN)$ in the presence of an alkali (like $NaOH$) proceeds through the formation of $acetamide$ $(CH_3CONH_2)$ as an intermediate,which further undergoes hydrolysis to form $acetate$ ions. Upon acidification,this yields $acetic \ acid$ $(CH_3COOH)$.The reaction is:$CH_3-C \equiv N + 2H_2O \xrightarrow{OH^-} CH_3COOH + NH_3$

Class 12 Chemistry 8-2.Carboxylic acids and Their derivative Preparation of Carboxylic Acids and Their Derivatives

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When $methyl \ cyanide$ is hydrolysed in the presence of an alkali,the final product is:

A
Acetamide
B
Methane
C
$CO_2 + H_2O$
D
Acetic acid

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8-2.Carboxylic acids and Their derivative

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Preparation of Carboxylic Acids and Their Derivatives

Identify the product $B$ in the following reaction.
Dry ice $\xrightarrow[\text{dry ether}]{CH_3MgBr} A$ $\xrightarrow{H_3O^{+}} B$

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What is obtained by the hydrolysis of methyl cyanide in the presence of an acid?

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The end product $B$ in the sequence of reactions: $R - X$ $\xrightarrow{KCN} A$ $\xrightarrow[H_2O]{NaOH} B$ is

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What is obtained when glycerol is heated with oxalic acid at $110\,^{\circ}C$?

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The reaction $CH_3-CH=CH_2 \xrightarrow[H^{+}]{CO + H_2O} CH_3-CH(COOH)-CH_3$ is known as:

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When $methyl \ cyanide$ is hydrolysed in the presence of an alkali,the final product is:

Similar Questions

Identify the product $B$ in the following reaction.Dry ice $\xrightarrow[\text{dry ether}]{CH_3MgBr} A$ $\xrightarrow{H_3O^{+}} B$

What is obtained by the hydrolysis of methyl cyanide in the presence of an acid?

The end product $B$ in the sequence of reactions: $R - X$ $\xrightarrow{KCN} A$ $\xrightarrow[H_2O]{NaOH} B$ is

What is obtained when glycerol is heated with oxalic acid at $110\,^{\circ}C$?

The reaction $CH_3-CH=CH_2 \xrightarrow[H^{+}]{CO + H_2O} CH_3-CH(COOH)-CH_3$ is known as:

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Identify the product $B$ in the following reaction.
Dry ice $\xrightarrow[\text{dry ether}]{CH_3MgBr} A$ $\xrightarrow{H_3O^{+}} B$