When heat is given to a gas in an isothermal change,the result will be

One mole of an ideal gas expands from an initial volume of $10 \; L$ to a final volume of $20 \; L$ at a constant temperature of $300 \; K$. Calculate the work done by the gas in $J$. $(R = 8.31 \; J/mol \cdot K)$ (in $; J$)

When an ideal gas in a cylinder was compressed isothermally by a piston,the work done on the gas was found to be $1.5 \times 10^4 \ J$. During this process,about:

The change in the entropy of $1$ mole of an ideal gas which undergoes an isothermal process from an initial state $(P_1, V_1, T)$ to the final state $(P_2, V_2, T)$ is equal to

Two moles of helium gas are taken over the cycle $ABCDA$,as shown in the $P-T$ diagram. The work done on the gas in taking it from $D$ to $A$ is

In an isothermal change, an ideal gas obeys: