When ethyl bromide reacts with sodium acetyli | vedclass

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(A) The reaction between ethyl bromide $(C_2H_5Br)$ and sodium acetylide $(NaC \equiv CH)$ is a nucleophilic substitution reaction $(S_N2)$.In this re

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but$-1-$yne

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(A) The reaction between ethyl bromide $(C_2H_5Br)$ and sodium acetylide $(NaC \equiv CH)$ is a nucleophilic substitution reaction $(S_N2)$.In this reaction,the acetylide ion $(C \equiv CH^-)$ acts as a nucleophile and attacks the ethyl bromide,displacing the bromide ion.The chemical equation is:$C_2H_5Br + NaC \equiv CH 	o C_2H_5C \equiv CH + NaBr$The product formed is $C_2H_5-C \equiv CH$,which is $but-1-yne$.

When ethyl bromide reacts with sodium acetylide,the main product is:

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