A metallic carbide on treatment with water gi | vedclass

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Question

(C) The metallic carbide is calcium carbide $(CaC_2)$.When $CaC_2$ reacts with water,it produces acetylene ($C_2H_2$ or $CH \equiv CH$):$CaC_2 + 2\,H_

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Acetylene

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(C) The metallic carbide is calcium carbide $(CaC_2)$.When $CaC_2$ reacts with water,it produces acetylene ($C_2H_2$ or $CH \equiv CH$):$CaC_2 + 2\,H_2O 	o Ca(OH)_2 + C_2H_2$Acetylene is a colourless gas that burns readily in air.It reacts with ammoniacal silver nitrate (Tollens' reagent) to form a white precipitate of silver acetylide:$CH \equiv CH + 2\,[Ag(NH_3)_2]OH 	o AgC \equiv CAg \downarrow (	ext{white ppt.}) + 4\,NH_3 + 2\,H_2O$Therefore,the gas evolved is acetylene.

$A$ metallic carbide on treatment with water gives a colourless gas which burns readily in air and which gives a precipitate with ammoniacal silver nitrate solution. The gas evolved is:

Similar Questions

What is the product formed when two molecules of $HBr$ are added to $CH_3 - C \equiv CH$?

The product formed in the above reaction is

The incorrect statement regarding ethyne is

$CH_3 - C \equiv C - CH_3 \xrightarrow[CH_3COOH]{BH_3, THF} \text{Major product}$

$CH_3-C \equiv C-CH_3 \xrightarrow{(i) X, (ii) H_2O/Zn} CH_3-CO-CO-CH_3$. $X$ in the above reaction is:

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