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(D) The magnetic force acting on a charged particle moving in a magnetic field is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Since the force is al

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Energy and momentum both remain unchanged

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(D) The magnetic force acting on a charged particle moving in a magnetic field is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Since the force is always perpendicular to the velocity vector $\vec{v}$,the work done by the magnetic field on the electron is zero $(W = \vec{F} \cdot \vec{d} = 0)$.Because the work done is zero,the kinetic energy of the electron remains constant.Since the kinetic energy $(K = \frac{1}{2}mv^2)$ is constant and the mass $m$ is constant,the speed $v$ remains constant.Consequently,the magnitude of the momentum $(p = mv)$ also remains unchanged.Therefore,both energy and momentum remain unchanged.

When an electron beam passes through an electric field,it gains kinetic energy. If the same beam passes through a magnetic field,then:

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