When chlorine reacts with cold and dilute solution of sodium hydroxide,the products obtained are:

  • A
    $Cl^{-} + ClO^{-}$
  • B
    $Cl^{-} + ClO_2^{-}$
  • C
    $Cl^{-} + ClO_3^{-}$
  • D
    $Cl^{-} + ClO_4^{-}$

Explore More

Similar Questions

Which one will liberate $Br_2$ from $KBr$?

When $1 \ mol$ of fluorine reacts with $2 \ mol$ of hot and concentrated $KOH$,the products obtained are $KF$,$H_2O$,and $O_2$. The molar ratio of $KF$,$H_2O$,and $O_2$ produced is respectively:

Difficult
View Solution

$POCl_3$ is prepared by the reaction of:
$(I)$ $P_4 + SO_2Cl_2 \to$
$(II)$ $P_4 + SOCl_2 \to$
$(III)$ $PCl_5 + SO_2 \to$
$(IV)$ $PCl_5 + C_2H_5OH \to$

When $I_2$ is dissolved in $CCl_4$,the colour that results is

Bromine is obtained commercially from sea water by adding

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo