When $1 \ mol$ of fluorine reacts with $2 \ mol$ of hot and concentrated $KOH$,the products obtained are $KF$,$H_2O$,and $O_2$. The molar ratio of $KF$,$H_2O$,and $O_2$ produced is respectively:
- A$1 : 1 : 2$
- B$2 : 1 : 0.5$
- C$1 : 2 : 1$
- D$2 : 1 : 2$
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