When an unpolarized light falls at a particular angle on a glass plate (placed in air),it is observed that the reflected beam is linearly polarized. The angle of the refracted beam with respect to the normal is . . . . . . . $(\tan ^{-1}(1.52)=57.7^{\circ}$,refractive indices of air and glass are $1.00$ and $1.52$,respectively) (in $^{\circ}$)

When the angle of incidence on a material is $60^\circ,$ the reflected light is completely polarized. The velocity of the refracted ray inside the material is (in $m/s$)

The velocity of light in air is $3 \times 10^8 \, ms^{-1}$ and that in water is $2.2 \times 10^8 \, ms^{-1}$. The polarising angle of incidence is.......$^o$

Given below are two statements:
Statement $I$: If the Brewster's angle for the light propagating from air to glass is $\theta_B$,then Brewster's angle for the light propagating from glass to air is $\frac{\pi}{2} - \theta_B$.
Statement $II$: The Brewster's angle for the light propagating from glass to air is $\tan^{-1}(\mu_g)$ where $\mu_g$ is the refractive index of glass.
In the light of the above statements,choose the correct answer from the options given below:

$A$ beam of light both reflects and refracts at the surface between air and glass. The refractive index of the glass is $1.4$. If the refracted and the reflected rays are perpendicular to each other,then the angle of incidence in the air is

At what angle should an unpolarised beam be incident on a crystal of $\mu = \sqrt{3}$,so that the reflected beam is polarised (in $^{\circ}$)?