When an ideal diatomic gas undergoes adiabatic expansion,if the increase in its volume is $0.5 \%$,then the change in the pressure of the gas is

During the adiabatic expansion of $2$ moles of a gas,the internal energy of the gas is found to decrease by $2 \ J$. The work done during the process on the gas will be equal to ....... $J$.

One mole of an ideal gas expands adiabatically at constant pressure such that its temperature $T \propto \frac{1}{\sqrt{V}}$. The value of $\gamma$ for the gas is $(\gamma = \frac{C_p}{C_v}, V = \text{Volume of the gas})$

In a process,the work done by the system is equal to the decrease in its internal energy. The process that the system undergoes is

$A$ fixed amount of a gas undergoes a thermodynamic process as shown in the figure,such that the heat interaction along path $B \to C \to A$ is equal to the work done by the gas along path $A \to B \to C$. Then the process $A \to B$ is:

$A$ monoatomic ideal gas,initially at temperature $T_1$,is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature $T_2$ by releasing the piston suddenly. $L_1$ and $L_2$ are the lengths of the gas columns before and after the expansion,respectively. The ratio $T_2 / T_1$ is