When an aqueous solution of copper $(II)$ sulphate is saturated with ammonia,the blue compound crystallises on evaporation. The formula of this blue compound is
- A$[Cu(NH_3)_4]SO_4 \cdot H_2O$ (square planar)
- B$[Cu(NH_3)SO_4]$ (tetrahedral)
- C$[Cu(NH_3)_6]SO_4$ (octahedral)
- D$[Cu(SO_4)(NH_3)_4]$ (octahedral)
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Similar Questions
Which of the following complexes does not involve inner orbital hybridization?
Difficult
View SolutionWhich of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$
Medium
View SolutionFrom the magnetic behaviour of $[NiCl_4]^{2-}$ (paramagnetic) and $[Ni(CO)_4]$ (diamagnetic),choose the correct geometry and oxidation state.
DifficultJEE MAIN 2025
View SolutionMatch the coordination number and type of hybridisation with distribution of hybrid orbitals in space based on Valence bond theory.
Coordination number and type of hybridisation Distribution of hybrid orbitals in space $(a)$. $4, sp^3$ $(i)$. trigonal bipyramidal $(b)$. $3, sp^2$ $(ii)$. octahedral $(c)$. $5, sp^3 d$ $(iii)$. tetrahedral $(d)$. $6, sp^3 d^2$ $(iv)$. trigonal planar
Select the correct option $:$
| Coordination number and type of hybridisation | Distribution of hybrid orbitals in space |
|---|---|
| $(a)$. $4, sp^3$ | $(i)$. trigonal bipyramidal |
| $(b)$. $3, sp^2$ | $(ii)$. octahedral |
| $(c)$. $5, sp^3 d$ | $(iii)$. tetrahedral |
| $(d)$. $6, sp^3 d^2$ | $(iv)$. trigonal planar |
Select the correct option $:$
Medium
View SolutionAmong $Ni(CO)_4, [Ni(CN)_4]^{2-}$ and $[NiCl_4]^{2-}$,which of the following statements is correct?
Medium
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