When a photosensitive surface is irradiated b | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{max}$ is given by $K_{max} = \frac{hc}{\lambda} - W$,where $W$ is th

Vedclass · Accepted Answer

$\frac{\lambda_1 E_1 - \lambda_2 E_2}{\lambda_2 - \lambda_1}$

Vedclass · Answer

(A) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{max}$ is given by $K_{max} = \frac{hc}{\lambda} - W$,where $W$ is the work function.For wavelength $\lambda_1$,$E_1 = \frac{hc}{\lambda_1} - W$  --- $(1)$For wavelength $\lambda_2$,$E_2 = \frac{hc}{\lambda_2} - W$  --- $(2)$From $(1)$,$hc = \lambda_1(E_1 + W)$.From $(2)$,$hc = \lambda_2(E_2 + W)$.Equating the two expressions for $hc$:$\lambda_1(E_1 + W) = \lambda_2(E_2 + W)$$\lambda_1 E_1 + \lambda_1 W = \lambda_2 E_2 + \lambda_2 W$$\lambda_1 E_1 - \lambda_2 E_2 = W(\lambda_2 - \lambda_1)$$W = \frac{\lambda_1 E_1 - \lambda_2 E_2}{\lambda_2 - \lambda_1}$

When a photosensitive surface is irradiated by light of wavelength $\lambda_1$ and $\lambda_2$,the maximum kinetic energies of the emitted photoelectrons are $E_1$ and $E_2$ respectively. The work function of the photosensitive surface is:

Similar Questions

The difference between threshold wavelengths for two metal surfaces $A$ and $B$ having work functions $\phi_A = 9 \, eV$ and $\phi_B = 4.5 \, eV$ in $nm$ is: (Given,$hc = 1242 \, eV \, nm$)

When $UV$ light of wavelength $300 \, nm$ is incident on a metal surface having a work function of $2.13 \, eV$, electron emission takes place. The stopping potential is: (Given $hc = 1240 \, eV \cdot nm$) (in $ \, V$)

If the frequency of light in a photoelectric experiment is doubled,the stopping potential will

Light emitted during the de-excitation of an electron from $n=3$ to $n=2$ is incident on a metal, and photoelectrons are just emitted from that metal. In which of the following de-excitations is the photoelectric effect $NOT$ possible?

The variation of stopping potential $(V_0)$ as a function of the frequency $\nu \ (\times 10^{14} \ Hz)$ of the incident light for a metal is shown in the figure. The work function of the surface is $........... \ eV$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module