When a hydrogen atom is raised from the groun | vedclass

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(A) The kinetic energy $(K.E.)$ of an electron in a hydrogen atom is given by $K.E. = \frac{kZe^2}{2r}$.Since $K.E. \propto \frac{1}{r}$,as the electr

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potential energy increases and $K$.$E$. decreases.

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(A) The kinetic energy $(K.E.)$ of an electron in a hydrogen atom is given by $K.E. = \frac{kZe^2}{2r}$.Since $K.E. \propto \frac{1}{r}$,as the electron moves to a higher energy level (excited state),the radius $r$ increases,which causes the $K.E.$ to decrease.The potential energy $(P.E.)$ is given by $P.E. = -\frac{kZe^2}{r}$.Since $P.E. \propto -\frac{1}{r}$,as $r$ increases,the magnitude of the negative value decreases,meaning the value of $P.E.$ becomes less negative (i.e.,it increases).Therefore,when a hydrogen atom is raised from the ground state to an excited state,its potential energy increases and its kinetic energy decreases.

When a hydrogen atom is raised from the ground state to the excited state,

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