When a charged particle moving with velocity $\vec{V}$ is subjected to a magnetic field of induction $\vec{B}$,the force on it is non-zero. This implies that the:

  • A
    Angle between $\vec{V}$ and $\vec{B}$ is necessarily $90^{\circ}$.
  • B
    Angle between $\vec{V}$ and $\vec{B}$ can have any value other than $90^{\circ}$.
  • C
    Angle between $\vec{V}$ and $\vec{B}$ can have any value other than $0^{\circ}$ and $180^{\circ}$.
  • D
    Angle between $\vec{V}$ and $\vec{B}$ is either $0^{\circ}$ or $180^{\circ}$.

Explore More

Similar Questions

$A$ charged particle is moving in a uniform magnetic field in a circular path of radius $R$. When the kinetic energy of the particle is increased to three times,then the new radius will be

An ionized gas contains both positive and negative ions. If it is subjected simultaneously to an electric field along the $+x$ direction and a magnetic field along the $+z$ direction,then

Which of the following,while in motion,cannot be deflected by a magnetic field?

Two ions having masses in the ratio $1: 1$ and charges $1: 2$ are projected into a uniform magnetic field perpendicular to the field with speeds in the ratio $2: 3$. The ratio of the radii of circular paths along which the two particles move is :

An $\alpha$-particle travels in a circular path of radius $0.45\,m$ in a magnetic field $B = 1.2\,Wb/m^2$ with a speed of $2.6 \times 10^7\,m/s$. The period of revolution of the $\alpha$-particle is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo