When a $4\, kg$ mass is hung vertically on a light spring that obeys Hooke's law, the spring stretches by $2\, cms$. The work required to be done by an external agent in stretching this spring by $5\, cms$ will be ......... $joule$       $(g = 9.8\,metres/se{c^2})$

  • A

    $4.90$

  • B

    $2.45$

  • C

    $0.495$

  • D

    $0.245$

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  • [AIIMS 2001]