When 2-Methylbut-2-ene is treated with hydrog | vedclass

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(B) The reaction of $2-$Methylbut$-2-$ene with $HCl$ follows Markovnikov's rule.According to Markovnikov's rule,the negative part of the addendum $(Cl

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$2-$Chloro$-2-$methylbutane

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(B) The reaction of $2-$Methylbut$-2-$ene with $HCl$ follows Markovnikov's rule.According to Markovnikov's rule,the negative part of the addendum $(Cl^-)$ attaches to the carbon atom of the double bond that has fewer hydrogen atoms.In $CH_3-C(CH_3)=CH-CH_3$,the carbon at position $2$ has no hydrogen,while the carbon at position $3$ has one hydrogen.Therefore,the $Cl^-$ ion attacks the carbon at position $2$,leading to the formation of $2-$Chloro$-2-$methylbutane as the major product.

When $2-$Methylbut$-2-$ene is treated with hydrogen chloride,the major product obtained is

Similar Questions

What is the major product formed by the reaction of $2$-methylpropene with $HBr$?

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Assertion : $trans-2-Butene$ on reaction with $Br_2$ gives $meso-2,3-dibromobutane$.
Reason : The reaction involves $syn-addition$ of bromine.

Rank the following alkenes in order of increasing $\lambda_{max}$:
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The correct structure of the product $A$ formed in the reaction shown below is:
$Cyclohex-2-en-1-one \xrightarrow[{Pd/C, \text{ ethanol}}]{{H_2 \text{ (gas, 1 atm)}}} A$

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