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(D) The reaction of $2$-methylpropene $(CH_3)_2C=CH_2$ with $HBr$ follows Markovnikov's rule.According to Markovnikov's rule,the electrophile $H^+$ ad

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$2$-bromo-$2$-methylpropane

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(D) The reaction of $2$-methylpropene $(CH_3)_2C=CH_2$ with $HBr$ follows Markovnikov's rule.According to Markovnikov's rule,the electrophile $H^+$ adds to the carbon atom with more hydrogen atoms,and the nucleophile $Br^-$ adds to the carbon atom with fewer hydrogen atoms.This leads to the formation of a stable tertiary carbocation intermediate $(CH_3)_3C^+$.Finally,the bromide ion attacks the tertiary carbocation to form $2$-bromo-$2$-methylpropane $(CH_3)_3CBr$ as the major product.

What is the major product formed by the reaction of $2$-methylpropene with $HBr$?

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