When 3, 3-dimethyl-2-butanol is heated with { | vedclass

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Question

(C) The dehydration of $3, 3-$dimethyl$-2-$butanol with ${H_2SO_4}$ proceeds via the formation of a carbocation.$1.$ Protonation of the alcohol group

Vedclass · Accepted Answer

$2, 3-$dimethyl$-2-$butene

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(C) The dehydration of $3, 3-$dimethyl$-2-$butanol with ${H_2SO_4}$ proceeds via the formation of a carbocation.$1.$ Protonation of the alcohol group leads to the formation of a $2^o$ carbocation: $CH_3-CH^+-C(CH_3)_2-CH_3$.$2.$ This $2^o$ carbocation undergoes a $1, 2-$methyl shift to form a more stable $3^o$ carbocation: $CH_3-CH(CH_3)-C^+(CH_3)-CH_3$.$3.$ Loss of a proton from the $3^o$ carbocation yields the most stable alkene,which is $2, 3-$dimethyl$-2-$butene,according to Saytzeff's rule.

When $3, 3-$dimethyl$-2-$butanol is heated with ${H_2SO_4}$,the major product obtained is:

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