What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?

  • A
    $Cr^{3+}$ and $Cr_2O_7^{2-}$ are formed
  • B
    $Cr_2O_7^{2-}$ and $H_2O$ are formed
  • C
    $CrO_4^{2-}$ is reduced to $+3$ state of $Cr$
  • D
    $CrO_4^{2-}$ is oxidized to $+7$ state of $Cr$

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