What would be the compound interest (In Rs.) | vedclass

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Question

$CI = P \left[\left(1+\frac{ R }{100}ight)^{2}-1ight]=7850 	imes\left[\left(1+\frac{14}{100}ight)^{2}-1ight]$

$=7850 	imes\left(\frac{114

Vedclass · Accepted Answer

$2351.86$

Vedclass · Answer

$CI = P \left[\left(1+\frac{ R }{100}ight)^{2}-1ight]=7850 	imes\left[\left(1+\frac{14}{100}ight)^{2}-1ight]$

$=7850 	imes\left(\frac{114}{100} 	imes \frac{114}{100}-1ight)=7850\left[\frac{12996-10000}{10000}ight]$

$=7850 	imes \frac{2996}{10000}= Rs .2351 .86$

What would be the compound interest (In $Rs.$) accrued on an amount of $Rs. 7850$ at the rate of $14$ $p.c.p.a.$ in $2$ years?

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