The simple interest on a certain sum of money | vedclass

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Question

Let the sum be $P$.

S.I. for 3 years $=\frac{P 	imes 3 	imes 8}{100}$

C.I. (for $₹ 4000 @ 10 \%$ p.a for 2 year $)=4000\left(1+\frac{10}{100}\

Vedclass · Accepted Answer

$1750$

Vedclass · Answer

Let the sum be $P$.

S.I. for 3 years $=\frac{P 	imes 3 	imes 8}{100}$

C.I. (for $₹ 4000 @ 10 \%$ p.a for 2 year $)=4000\left(1+\frac{10}{100}ight)^{2}-4000$

$=4000\left[\left(\frac{11}{10}ight)^{2}-1ight]=4000 	imes\left(\frac{11^{2}-10^{2}}{10^{2}}ight)$

$=40 	imes 21=840$

$	herefore \quad$ From (1) and (2)

$P 	imes \frac{3 	imes 8}{100}=\frac{1}{2} 	imes C.I. =\frac{1}{2} 	imes 840=420$

$P=\frac{420 	imes 100}{24}=70 	imes 25=₹ 1750$

The simple interest on a certain sum of money for $3$ years at $8 \%$ per annum is half the compound interest on ₹ $4000$ for $2$ years at $10 \%$ per annum. The sum placed on simple interest (In ₹) is

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