What will be the work done on an ideal gas enclosed in a cylinder,when it is compressed by a constant external pressure,$p_{ext}$ in a single step as shown in the figure? Explain graphically.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The change in volume is given by $\Delta V = (V_f - V_i)$.
If $W$ is the work done on the system by the movement of the piston,then the work done is defined as:
$W = -p_{ext} \times \Delta V$
Substituting $\Delta V = (V_f - V_i)$,we get:
$W = -p_{ext} \times (V_f - V_i) = p_{ext} \times (V_i - V_f)$
This can be represented on a $p-V$ graph as shown in the figure. The work done is equal to the shaded area under the pressure-volume curve.
In the case of compression,the system is compressed from initial volume $V_i$ to final volume $V_f$,where $V_f < V_i$. Thus,$\Delta V$ is negative,making the work done $W$ positive,which is consistent with the sign convention that work done on the system is positive.

Explore More

Similar Questions

Work done during isothermal expansion of $1 \, \text{mole}$ of an ideal gas from $10 \, \text{atm}$ to $1 \, \text{atm}$ at $300 \, \text{K}$ is ....... $\text{cal}$ (Gas constant $R = 2 \, \text{cal} \, \text{K}^{-1} \, \text{mol}^{-1}$) (in $.8$)

Which of the following statements is not correct?

What is meant by standard state in the context of the equation $\Delta U = q + w$?

Which of the following expressions is true for an ideal gas?

Identify the process from the following such that the volume of the system remains constant.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo