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(C) The given reaction is $C_2H_{4(g)} + H_{2(g)} \rightarrow C_2H_{6(g)}$.This is a hydrogenation reaction which typically follows second-order kinet

Vedclass · Accepted Answer

$mol^{-1} \cdot L \cdot s^{-1}$

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(C) The given reaction is $C_2H_{4(g)} + H_{2(g)} \rightarrow C_2H_{6(g)}$.This is a hydrogenation reaction which typically follows second-order kinetics.The general formula for the unit of the rate constant $k$ for an $n^{th}$ order reaction is $(mol \cdot L^{-1})^{1-n} \cdot s^{-1}$.For a second-order reaction,$n = 2$.Substituting $n = 2$ into the formula: $(mol \cdot L^{-1})^{1-2} \cdot s^{-1} = (mol \cdot L^{-1})^{-1} \cdot s^{-1} = mol^{-1} \cdot L \cdot s^{-1}$.Therefore,the correct unit is $mol^{-1} \cdot L \cdot s^{-1}$,which corresponds to option $C$.

What will be the unit of the rate constant for the following reaction?
$C_2H_{4(g)} + H_{2(g)} \rightarrow C_2H_{6(g)}$

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What will be the unit of the rate constant for the following reaction?$C_2H_{4(g)} + H_{2(g)} \rightarrow C_2H_{6(g)}$