What will be the force constant of the spring | vedclass

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(B) In the given figure,the two springs with force constant $k_1$ are connected in parallel. The equivalent force constant of these two springs is $k_

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${\left[ {\frac{1}{{2{K_1}}} + \frac{1}{{{K_2}}}} \right]^{ - 1}}$

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(B) In the given figure,the two springs with force constant $k_1$ are connected in parallel. The equivalent force constant of these two springs is $k_p = k_1 + k_1 = 2k_1$.Now,this equivalent spring is connected in series with the spring having force constant $k_2$.For a series combination of two springs with force constants $k_p$ and $k_2$,the equivalent force constant $k_S$ is given by:$\frac{1}{k_S} = \frac{1}{k_p} + \frac{1}{k_2}$Substituting $k_p = 2k_1$,we get:$\frac{1}{k_S} = \frac{1}{2k_1} + \frac{1}{k_2}$Therefore,the equivalent force constant is:$k_S = \left[ \frac{1}{2k_1} + \frac{1}{k_2} \right]^{-1}$

What will be the force constant of the spring system shown in the figure?

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