What will be the energy released in joule,in | vedclass

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(C) The number of moles $n$ is given by $n = \frac{m}{M} = \frac{N}{N_A}$,where $m$ is the mass,$M$ is the molar mass,$N$ is the number of atoms,and $

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$8.0 	imes 10^7 	ext{ J}$

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(C) The number of moles $n$ is given by $n = \frac{m}{M} = \frac{N}{N_A}$,where $m$ is the mass,$M$ is the molar mass,$N$ is the number of atoms,and $N_A$ is Avogadro's number.Given $m = 1 	ext{ mg} = 10^{-3} 	ext{ g}$,$M = 240 	ext{ g/mol}$,and $N_A = 6 	imes 10^{23} 	ext{ atoms/mol}$.The number of atoms $N$ is:$N = \frac{m}{M} 	imes N_A = \frac{10^{-3}}{240} 	imes 6 	imes 10^{23} = 2.5 	imes 10^{18} 	ext{ atoms}$.The energy released per fission is $E_f = 200 	ext{ MeV} = 200 	imes 10^6 	imes 1.6 	imes 10^{-19} 	ext{ J} = 3.2 	imes 10^{-11} 	ext{ J}$.Total energy released $E = N 	imes E_f = 2.5 	imes 10^{18} 	imes 3.2 	imes 10^{-11} 	ext{ J} = 8.0 	imes 10^7 	ext{ J}$.

$A. \text{ } _0^1 n + { }_{92}^{235} U \rightarrow { }_{54}^{140} Xe + { }_{38}^{94} Sr + 2_0^1 n$	$I. \text{ Chemical reaction}$
$B. \text{ } 2H_2 + O_2 \rightarrow 2H_2O$	$II. \text{ Fusion with } +ve \ Q \text{ value}$
$C. \text{ } _1^2 H + _1^2 H \rightarrow _2^3 He + _0^1 n$	$III. \text{ Fission}$
$D. \text{ } _1^1 H + _1^3 H \rightarrow _1^2 H + _1^2 H$	$IV. \text{ Fusion with } -ve \ Q \text{ value}$

What will be the energy released in joule,in the process of fission by $1 \text{ mg}$ of ${ }_{92}^{240} U$? Assume energy release per fission is $200 \text{ MeV}$. [Use Avogadro's number as $6 \times 10^{23}$ and $1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}$]

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