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(D) Simple Interest ($S$.$I$.) on ₹ $1000$ at $10 \%$ per annum for $4$ years is calculated as:$S.I. = \frac{P 	imes R 	imes T}{100} = \frac{1000

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$64.10$

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(D) Simple Interest ($S$.$I$.) on ₹ $1000$ at $10 \%$ per annum for $4$ years is calculated as:$S.I. = \frac{P 	imes R 	imes T}{100} = \frac{1000 	imes 10 	imes 4}{100} = ₹ 400$.Compound Interest ($C$.$I$.) on ₹ $1000$ at $10 \%$ per annum for $4$ years is calculated as:$C.I. = P \left[ \left( 1 + \frac{R}{100} ight)^T - 1 ight] = 1000 \left[ \left( 1 + \frac{10}{100} ight)^4 - 1 ight]$$= 1000 \left[ (1.1)^4 - 1 ight] = 1000 [1.4641 - 1] = 1000 	imes 0.4641 = ₹ 464.10$.The difference between Compound Interest and Simple Interest is:$C.I. - S.I. = 464.10 - 400 = ₹ 64.10$.

What will be the difference between simple and compound interest (in ₹) at $10 \%$ per annum on a sum of ₹ $1000$ after $4$ years?

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