What will be the angular momentum of an elect | vedclass

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(C) The energy of an electron in the $n^{th}$ orbit of a Hydrogen atom is given by $E_n = -\frac{13.6}{n^2} \, eV$.Given $E_n = -1.5 \, eV$,we have $-

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$3.15 	imes 10^{-34}$

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(C) The energy of an electron in the $n^{th}$ orbit of a Hydrogen atom is given by $E_n = -\frac{13.6}{n^2} \, eV$.Given $E_n = -1.5 \, eV$,we have $-1.5 = -\frac{13.6}{n^2}$.$n^2 = \frac{13.6}{1.5} \approx 9.06$,which implies $n \approx 3$.According to Bohr's postulate,the angular momentum $L$ is given by $L = n \frac{h}{2\pi}$.Substituting $n = 3$ and $h = 6.626 	imes 10^{-34} \, J \cdot s$:$L = 3 	imes \frac{6.626 	imes 10^{-34}}{2 	imes 3.14159} \approx 3 	imes 1.054 	imes 10^{-34} \approx 3.16 	imes 10^{-34} \, J \cdot s$.Rounding to the provided options,the correct value is $3.15 	imes 10^{-34} \, J \cdot s$.

What will be the angular momentum of an electron,if the energy of this electron in an $H$-atom is $-1.5 \, eV$ (in $J \cdot s$)?

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