What will be the pH and alpha (degree of hydr | vedclass

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(B) For a salt of a weak acid and a weak base,the degree of hydrolysis $(h)$ is given by: $h = \sqrt{\frac{K_w}{K_a K_b}}$.Given $K_w = 10^{-14}$,$K_a

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$7, 10\%$

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(B) For a salt of a weak acid and a weak base,the degree of hydrolysis $(h)$ is given by: $h = \sqrt{\frac{K_w}{K_a K_b}}$.Given $K_w = 10^{-14}$,$K_a = 10^{-6}$,and $K_b = 10^{-6}$.$h = \sqrt{\frac{10^{-14}}{10^{-6} 	imes 10^{-6}}} = \sqrt{\frac{10^{-14}}{10^{-12}}} = \sqrt{10^{-2}} = 0.1$.Therefore,$\alpha = 0.1$ or $10\%$.The $pH$ of a salt of a weak acid and a weak base is given by: $pH = 7 + \frac{1}{2}(pK_a - pK_b)$.Since $K_a = K_b = 10^{-6}$,$pK_a = pK_b = 6$.$pH = 7 + \frac{1}{2}(6 - 6) = 7 + 0 = 7$.Thus,the $pH$ is $7$ and $\alpha$ is $10\%$.

What will be the $pH$ and $\alpha$ (degree of hydrolysis) respectively for the salt $BA$ of $0.1 \ M$ concentration? (Given: $K_a$ for $HA = 10^{-6}$ and $K_b$ for $BOH = 10^{-6}$)

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