Which salt represents the highest degree of h | vedclass

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Question

(B) The degree of hydrolysis $(h)$ for a salt depends on the strength of the acid and base from which it is derived. $NaCl$ is a salt of a strong acid

Vedclass · Accepted Answer

$CH_3COONH_4$

Vedclass · Answer

(B) The degree of hydrolysis $(h)$ for a salt depends on the strength of the acid and base from which it is derived. $NaCl$ is a salt of a strong acid $(HCl)$ and a strong base $(NaOH)$,so it does not undergo hydrolysis. $CH_3COONa$ is a salt of a weak acid $(CH_3COOH)$ and a strong base $(NaOH)$,which undergoes anionic hydrolysis. $NH_4Cl$ is a salt of a strong acid $(HCl)$ and a weak base $(NH_4OH)$,which undergoes cationic hydrolysis. $CH_3COONH_4$ is a salt of a weak acid $(CH_3COOH)$ and a weak base $(NH_4OH)$. For a salt of a weak acid and a weak base,the degree of hydrolysis is given by $h = \sqrt{K_h} = \sqrt{\frac{K_w}{K_a 	imes K_b}}$. Since both $K_a$ and $K_b$ are small,the value of $h$ is significantly higher compared to salts derived from a strong acid/weak base or weak acid/strong base. Therefore,$CH_3COONH_4$ undergoes the highest degree of hydrolysis.

Which salt represents the highest degree of hydrolysis?

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