What type of hybridisation is present in squa | vedclass

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Question

(B) In the complex $[Ni(CN)_4]^{2-}$,the central metal ion is $Ni^{2+}$.The atomic number of $Ni$ is $28$,so the electronic configuration of $Ni^{2+}$

Vedclass · Accepted Answer

$dsp^2$

Vedclass · Answer

(B) In the complex $[Ni(CN)_4]^{2-}$,the central metal ion is $Ni^{2+}$.The atomic number of $Ni$ is $28$,so the electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.$CN^-$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.This results in one empty $3d$ orbital,one $4s$ orbital,and two $4p$ orbitals being available for hybridisation.Thus,the hybridisation involved is $dsp^2$,which corresponds to a square planar geometry.

List-$I$	List-$II$
$A. K_2[Ni(CN)_4]$	$I. sp^3$
$B. [Ni(CO)_4]$	$II. sp^3d^2$
$C. [Co(NH_3)_6]Cl_3$	$III. dsp^2$
$D. Na_3[CoF_6]$	$IV. d^2sp^3$

What type of hybridisation is present in square planar geometry of complex $[Ni(CN)_4]^{2-}$?

Similar Questions

$[Mn(CO)_4 NO]$ is diamagnetic because

Match List-$I$ with List-$II$:

List-$I$ List-$II$

$A. K_2[Ni(CN)_4]$ $I. sp^3$

$B. [Ni(CO)_4]$ $II. sp^3d^2$

$C. [Co(NH_3)_6]Cl_3$ $III. dsp^2$

$D. Na_3[CoF_6]$ $IV. d^2sp^3$

Choose the correct answer from the options given below:

Which one of the following ions is not tetrahedral in shape?

The hybridisation and geometry of $[Ni(CN)_4]^{2-}$ are:

Which of the following is true for the $[NiCl_4]^{2-}$ complex?

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