The hybridisation and geometry of [Ni(CN)_4]^ | vedclass

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(D) The oxidation state of $Ni$ in $[Ni(CN)_4]^{2-}$ is $+2$. The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8 4s^0$. Since $CN^-$ is a strong

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$dsp^2$ and square planar

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(D) The oxidation state of $Ni$ in $[Ni(CN)_4]^{2-}$ is $+2$. The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8 4s^0$. Since $CN^-$ is a strong field ligand,it causes the pairing of electrons in the $3d$ orbitals. This results in the availability of one $3d$,one $4s$,and two $4p$ orbitals for hybridisation,leading to $dsp^2$ hybridisation. Therefore,the complex $[Ni(CN)_4]^{2-}$ exhibits a square planar geometry.

The hybridisation and geometry of $[Ni(CN)_4]^{2-}$ are:

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