What map unit (Centimorgan) is adopted in the construction of genetic maps?
What map unit (Centimorgan) is adopted in the construction of genetic maps?
- [NEET 2019]
- A
Aunit of distance between two expressed genes, representing $10 \%$ cross over
- B
A unit of distance between two expressed genes, representing $100 \%$ cross over
- C
A unit of distance between genes on chromosomes, representing $1 \%$ cross over
- D
A unit of distance between genes on chromosomes, representing $50 \%$ cross over
Similar Questions
In order to calculate map distance of genes on a chromosome, one must know the
In order to calculate map distance of genes on a chromosome, one must know the
Which one of the following pairs is correctly matched
Which one of the following pairs is correctly matched
Select the correct statement from the ones given below with respect to dihybrid cross.
Select the correct statement from the ones given below with respect to dihybrid cross.
- [AIPMT 2010]
Percentage of recombination between $A$ and $B$ is $9\%$ and $C$ is $17\%$, $B$ and $C$ is $26\%$, then the arrangement of genes is
Percentage of recombination between $A$ and $B$ is $9\%$ and $C$ is $17\%$, $B$ and $C$ is $26\%$, then the arrangement of genes is
The recombination frequency between the genes $a\, \& \, c$ is $5 \,\% \,, b\, \& \,c$ is $15 \,\%,\, b\, \& \,d$ is $9 \%, \,a\, \& \,b$ is $20 \%$ , $c\, \& \,d$ is $24 \%$ and $a \, \& \,d$ is $29 \%$. What will be the sequence of these genes on a linear chromosome?
The recombination frequency between the genes $a\, \& \, c$ is $5 \,\% \,, b\, \& \,c$ is $15 \,\%,\, b\, \& \,d$ is $9 \%, \,a\, \& \,b$ is $20 \%$ , $c\, \& \,d$ is $24 \%$ and $a \, \& \,d$ is $29 \%$. What will be the sequence of these genes on a linear chromosome?
- [NEET 2022]