What is the shape and magnetic nature of the | vedclass

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(B) The permanganate ion $(MnO_4^-)$ has a tetrahedral geometry.In this ion,the manganese atom is in the $+7$ oxidation state,meaning it has a $d^0$ e

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Tetrahedral,diamagnetic

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(B) The permanganate ion $(MnO_4^-)$ has a tetrahedral geometry.In this ion,the manganese atom is in the $+7$ oxidation state,meaning it has a $d^0$ electronic configuration.The $\pi -$ bonding occurs due to the overlap of $p-$ orbitals of oxygen with $d-$ orbitals of manganese.Since there are no unpaired electrons in the $d^0$ configuration,the ion is diamagnetic.The structure is shown below:$Mn$ is at the center bonded to four oxygen atoms in a tetrahedral arrangement.

List $-I$	List $-II$
$A$. $[PtCl_4]^{2-}$	$I$. $sp^3d$
$B$. $BrF_5$	$II$. $d^2sp^3$
$C$. $PCl_5$	$III$. $dsp^2$
$D$. $[Co(NH_3)_6]^{3+}$	$IV$. $sp^3d^2$

What is the shape and magnetic nature of the permanganate ion $(MnO_4^-)$?

Similar Questions

The hybridization and magnetic behaviour of the cobalt ion in the $[Co(NH_3)_6]^{3+}$ complex,respectively,are:

Which of the following complexes exhibits outer orbital hybridization?

Which from the following statements about $[Co(NH_3)_6]^{3+}$ complex is $NOT$ correct?

Match List $-I$ with List $-II$:

List $-I$ List $-II$

$A$. $[PtCl_4]^{2-}$ $I$. $sp^3d$

$B$. $BrF_5$ $II$. $d^2sp^3$

$C$. $PCl_5$ $III$. $dsp^2$

$D$. $[Co(NH_3)_6]^{3+}$ $IV$. $sp^3d^2$

According to valence bond theory,the metal atom or ion can make use of which of the following orbitals to yield hybrid orbitals that can form bonds with ligands?

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