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(C) $1$. The oxidation state of $Co$ in $[Co(NH_3)_6]^{3+}$ is $+3$.$2$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.$3$. $NH_3$ is a str

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$d^2sp^3$ and diamagnetic

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(C) $1$. The oxidation state of $Co$ in $[Co(NH_3)_6]^{3+}$ is $+3$.$2$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.$3$. $NH_3$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.$4$. After pairing,the $3d$ orbitals have two vacant $d$-orbitals,one $4s$ orbital,and three $4p$ orbitals available for hybridization.$5$. This results in $d^2sp^3$ hybridization,which is inner orbital octahedral geometry.$6$. Since all electrons are paired in the $3d$ orbitals,the complex is diamagnetic.

The hybridization and magnetic behaviour of the cobalt ion in the $[Co(NH_3)_6]^{3+}$ complex,respectively,are:

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