What is the self-inductance of a solenoid of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The formula for the self-inductance $(L)$ of a solenoid is given by: $L = \frac{\mu_0 N^2 A}{l}$ Given: Permeability of free space $\mu_0 = 4 \pi

Vedclass · Accepted Answer

$4$ mH

Vedclass · Answer

(A) The formula for the self-inductance $(L)$ of a solenoid is given by: $L = \frac{\mu_0 N^2 A}{l}$ Given: Permeability of free space $\mu_0 = 4 \pi 	imes 10^{-7} \ T \cdot m/A$ Number of turns $N = 10^3$ Area of cross-section $A = 10^{-3} \ m^2$ Length $l = 31.4 \ cm = 31.4 	imes 10^{-2} \ m$ Substituting the values: $L = \frac{4 	imes 3.14 	imes 10^{-7} 	imes (10^3)^2 	imes 10^{-3}}{31.4 	imes 10^{-2}}$ $L = \frac{4 	imes 3.14 	imes 10^{-7} 	imes 10^6 	imes 10^{-3}}{31.4 	imes 10^{-2}}$ $L = \frac{12.56 	imes 10^{-4}}{31.4 	imes 10^{-2}} = \frac{12.56}{31.4} 	imes 10^{-2} = 0.4 	imes 10^{-2} \ H$ $L = 4 	imes 10^{-3} \ H = 4 \ mH$

What is the self-inductance of a solenoid of length $31.4 \ cm$,area of cross-section $10^{-3} \ m^2$,and total number of turns $10^3$?

Similar Questions

The current in a coil of self-inductance $2.0 \, H$ is increasing according to $I = 2 \sin(t^2) \, A$. The amount of energy spent during the period when current changes from $0$ to $2 \, A$ is ...... $J$.

$A$ circular coil of radius $R$ has $N$ turns of a wire. The coefficient of self-induction of the coil will be $(\mu_0 = \text{permeability of free space})$

$A$ coil is wound on a core of rectangular cross-section. If all the linear dimensions of the core are increased by a factor of $2$ and the number of turns per unit length of the coil remains the same, the self-inductance increases by a factor of (Assume, permeability is same).

In the given circuit,the bulb will become suddenly bright if:

Which of the following is not the unit of self-inductance?

Vedclass Test Series

Exam Paper Generator

Online Exam Module