What is the product obtained in the reaction?
$CH_3-CH=CH-CH_2-CHO \xrightarrow[(ii) H_3O^{+}]{(i) LiAlH_4} \text{product}$
$CH_3-CH=CH-CH_2-CHO \xrightarrow[(ii) H_3O^{+}]{(i) LiAlH_4} \text{product}$
- A$CH_3-CH=CH-CH_2-CH_2-OH$
- B$CH_3-CH=CH-CH_2-COOH$
- C$CH_3-CH_2-CH_2-CH_2-CHO$
- D$CH_3-CH_2-CH_2-CH_2-CH_3$
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