The end product in the reaction is:

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(B) The reaction sequence is as follows: $1$. The first step is the Reimer-Tiemann reaction,where phenol reacts with $CHCl_3$ and $OH^-$ to form $o$-h

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(B) The reaction sequence is as follows: $1$. The first step is the Reimer-Tiemann reaction,where phenol reacts with $CHCl_3$ and $OH^-$ to form $o$-hydroxybenzaldehyde (salicylaldehyde) as the intermediate product $X$. $2$. The second step involves the treatment of $o$-hydroxybenzaldehyde with $50\% \ NaOH$ (concentrated alkali),which leads to the Cannizzaro reaction. $3$. In the Cannizzaro reaction,the aldehyde group is disproportionated into an alcohol group $(-CH_2OH)$ and a carboxylate group $(-COO^-)$. $4$. Thus,the final products $Y$ and $Z$ are $2$-hydroxybenzyl alcohol and $2$-hydroxybenzoate ion,respectively.

Column-$I$ (Compound)	Column-$II$ (Attraction Forces)
$A$. Aldehyde	$i$. Intermolecular hydrogen bond formed in $ROH$ between $O^{\delta -}$ of one molecule and $H^{\delta +}$ of another molecule.
$B$. Ketone	$ii$. Dipole-dipole forces between $C^{\delta +}$ of one molecule and $O^{\delta -}$ of another molecule.
$C$. Alcohol	$iii$. van der Waals forces
$D$. Alkane	$iv$. Ionic forces

Similar Questions

Arrange the following compounds in increasing order of their enol content:
$1. CH_3CHO$
$2. CH_3COCH_3$
$3. CH_3COCH_2CHO$
$4. CH_3COCH_2COCH_3$

$(A)$ and $(B)$ in the following reaction sequence are:
$RR'C=O$ $\xrightarrow{HCN} (A)$ $\xrightarrow{B} RR'C(OH)CH_2NH_2$

Describe the various chemical reactions of aldehyde and ketone compounds.

In the following reaction,the major product $X$ is

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