(C) Let the oxidation number of sulphur $(S)$ be $x$. In $SO_3$,the oxidation number of oxygen $(O)$ is $-2$. The sum of oxidation numbers of all atom

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(C) Let the oxidation number of sulphur $(S)$ be $x$. In $SO_3$,the oxidation number of oxygen $(O)$ is $-2$. The sum of oxidation numbers of all atoms in a neutral molecule is $0$. Therefore,$x + 3(-2) = 0$. $x - 6 = 0$. $x = +6$. Thus,the oxidation number of sulphur in $SO_3$ is $+6$.