The oxidation number of carbon in CH_2Cl_2 is | vedclass

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Question

(A) Let the oxidation number of carbon be $x$.In $CH_2Cl_2$,the oxidation number of hydrogen $(H)$ is $+1$ and the oxidation number of chlorine $(Cl)$

Vedclass · Accepted Answer

$0$

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(A) Let the oxidation number of carbon be $x$.In $CH_2Cl_2$,the oxidation number of hydrogen $(H)$ is $+1$ and the oxidation number of chlorine $(Cl)$ is $-1$.The sum of oxidation numbers of all atoms in a neutral molecule is $0$.Therefore,$x + 2(+1) + 2(-1) = 0$.$x + 2 - 2 = 0$.$x = 0$.Thus,the oxidation number of carbon in $CH_2Cl_2$ is $0$.

The oxidation number of carbon in $CH_2Cl_2$ is .........

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