What is the new temperature of a gas when its | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Charles' law,at constant pressure,the volume of a fixed mass of gas is directly proportional to its absolute temperature: $\frac{V_1}

Vedclass · Accepted Answer

$600$

Vedclass · Answer

(B) According to Charles' law,at constant pressure,the volume of a fixed mass of gas is directly proportional to its absolute temperature: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given: $V_1 = 3 \ dm^3$,$T_1 = 300 \ K$,and $V_2 = 2 	imes V_1 = 6 \ dm^3$.Substituting the values into the equation: $\frac{3 \ dm^3}{300 \ K} = \frac{6 \ dm^3}{T_2}$.Solving for $T_2$: $T_2 = \frac{6 \ dm^3 	imes 300 \ K}{3 \ dm^3} = 600 \ K$.

What is the new temperature of a gas when its initial volume $3 \ dm^3$ at $300 \ K$ is doubled at constant pressure (in $K$)?

Similar Questions

The volume of a gas is $4 \ dm^3$ at $0^{\circ} C$. Calculate the new volume at constant pressure when the temperature is increased by $10^{\circ} C$. (in $dm^3$)

At $300 \, K$ temperature and $1 \, atm$ pressure,the volume of $7.0 \, g$ of a gas is $4.1 \, L$. What is the molar mass of the gas?

State the combined gas law and the ideal gas equation.

At $NTP$,$10 \ g$ of a gas occupies $5 \ L$ of volume. At what temperature will the volume become double for the same mass of gas at the same pressure?

The following graph illustrates:

Vedclass Test Series

Exam Paper Generator

Online Exam Module