At NTP,10 g of a gas occupies 5 L of volume | vedclass

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Question

(C) According to Charles's Law,for a fixed mass of gas at constant pressure,the volume is directly proportional to the absolute temperature: $V \p

Vedclass · Accepted Answer

$273 \ ^\circ C$

Vedclass · Answer

(C) According to Charles's Law,for a fixed mass of gas at constant pressure,the volume is directly proportional to the absolute temperature: $V \propto T$ or $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.
Given: $V_1 = 5 \ L$,$T_1 = 273 \ K$ (at $NTP$),$V_2 = 2 	imes V_1 = 10 \ L$.
Substituting the values: $\frac{5}{273} = \frac{10}{T_2}$.
$T_2 = \frac{10 	imes 273}{5} = 2 	imes 273 = 546 \ K$.
To convert to Celsius: $T(^\circ C) = T(K) - 273 = 546 - 273 = 273 \ ^\circ C$.

At $NTP$,$10 \ g$ of a gas occupies $5 \ L$ of volume. At what temperature will the volume become double for the same mass of gas at the same pressure?

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