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(D) The chemical formula for aluminium sulphate is $Al_2(SO_4)_3$. According to Kohlrausch's law of independent migration of ions,the molar conductivi

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$528.3$

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(D) The chemical formula for aluminium sulphate is $Al_2(SO_4)_3$. According to Kohlrausch's law of independent migration of ions,the molar conductivity at infinite dilution (zero concentration) is given by: $\Lambda_m^0 (Al_2(SO_4)_3) = 2 \lambda_m^0 (Al^{3+}) + 3 \lambda_m^0 (SO_4^{2-})$ Given: $\lambda_m^0 (Al^{3+}) = 189 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ $\lambda_m^0 (SO_4^{2-}) = 50.1 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ Substituting the values: $\Lambda_m^0 = 2(189) + 3(50.1)$ $\Lambda_m^0 = 378 + 150.3 = 528.3 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ Thus,the correct option is $D$.

What is the molar conductivity at zero concentration in $\Omega^{-1} \ cm^2 \ mol^{-1}$ for aluminium sulphate,if the molar ionic conductivities at zero concentration of $Al^{3+}$ and $SO_4^{2-}$ are $189 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and $50.1 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively?

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