The unit of equivalent conductivity is

  • A
    $ohm \ cm$
  • B
    $ohm^{-1} \ cm^2 \ (gm \ equivalent)^{-1}$
  • C
    $ohm \ cm^2 \ (gm \ equivalent)$
  • D
    $S \ cm^{-2}$

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Which one of the following solutions will have the highest conductivity?

Conductivity of a saturated solution of a sparingly soluble salt $AB$ at $298 \ K$ is $1.85 \times 10^{-5} \ S \ m^{-1}$. Solubility product of the salt $AB$ at $298 \ K$ is. Given $\Lambda_{m}^{\circ}(AB) = 140 \times 10^{-4} \ S \ m^{2} \ mol^{-1}$.

The equivalent conductivities of $Al^{3+}$ and $SO_4^{2-}$ ions at infinite dilution are $189$ and $160 \ \Omega^{-1} cm^2 eq^{-1}$ respectively. What is the equivalent conductivity of $Al_2(SO_4)_3$ at infinite dilution?

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The resistance of a conductivity cell filled with $0.1 \ M$ $KCl$ solution is $100 \ \Omega$. If the resistance of the same cell when filled with $0.02 \ M$ $KCl$ solution is $520 \ \Omega$,the molar conductivity of $0.02 \ M$ solution (in $S \ cm^2 \ mol^{-1}$) is (Given: conductivity of $0.1 \ M$ $KCl$ solution $= 1.29 \ S \ m^{-1}$)

$A$ conductivity cell containing $0.001 \ M$ $AgNO_3$ solution develops resistance $6530 \ \Omega$ at $25 \ ^{\circ}C$. Calculate the electrical conductivity of the solution at the same temperature if the cell constant is $0.653 \ cm^{-1}$.

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