What is the molar concentration of chloride i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The dissociation reactions are:$KCl \rightarrow K^{+} + Cl^{-}$$BaCl_2 \rightarrow Ba^{2+} + 2Cl^{-}$For $KCl$ solution:$Moles \ of \ Cl^{-} = M \

Vedclass · Accepted Answer

$5.0$

Vedclass · Answer

(A) The dissociation reactions are:$KCl ightarrow K^{+} + Cl^{-}$$BaCl_2 ightarrow Ba^{2+} + 2Cl^{-}$For $KCl$ solution:$Moles \ of \ Cl^{-} = M 	imes V = 3.0 \ M 	imes 0.3 \ L = 0.9 \ mol$For $BaCl_2$ solution:$Moles \ of \ Cl^{-} = 2 	imes M 	imes V = 2 	imes 4.0 \ M 	imes 0.2 \ L = 1.6 \ mol$Total moles of $Cl^{-} = 0.9 \ mol + 1.6 \ mol = 2.5 \ mol$Total volume of solution = $300 \ mL + 200 \ mL = 500 \ mL = 0.5 \ L$$[Cl^{-}] = \frac{	ext{Total moles of } Cl^{-}}{	ext{Total volume in } L} = \frac{2.5 \ mol}{0.5 \ L} = 5.0 \ M$

What is the molar concentration of chloride ion in a solution made by adding $300 \ mL$ of $3.0 \ M$ $KCl$ solution to $200 \ mL$ of $4.0 \ M$ $BaCl_2$ solution? $........ \ M$

Similar Questions

The molarity of the solution obtained by mixing $480 \, mL$ of $1.5 \, M$ solution with $500 \, mL$ of $1.2 \, M$ solution is ........ $M$.

$A$ molar solution is one that contains one mole of a solute in

The hardness of a water sample due to $MgSO_4$ is $50 \, ppm$. Calculate the amount of $MgSO_4$ in $mg$ present in $1 \, kg$ of water.

Calculate the amount of benzoic acid $(C_{6}H_{5}COOH)$ required for preparing $250 \ mL$ of $0.15 \ M$ solution in methanol.

$10.6 \, g$ of a substance of molecular weight $106$ was dissolved in $100 \, mL$. $10 \, mL$ of this solution was pipetted out into a $1000 \, mL$ flask and made up to the mark with distilled water. The molarity of the resulting solution is

Vedclass Test Series

Exam Paper Generator

Online Exam Module