The hardness of a water sample due to MgSO_4 | vedclass

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(B) Hardness in $ppm$ is defined as the mass of solute in $mg$ per $10^6 \, mg$ of water.Since $1 \, kg$ of water is equal to $1000 \, g$ or $10^6 \,

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(B) Hardness in $ppm$ is defined as the mass of solute in $mg$ per $10^6 \, mg$ of water.Since $1 \, kg$ of water is equal to $1000 \, g$ or $10^6 \, mg$,the concentration in $ppm$ is numerically equal to the mass of the solute in $mg$ per $1 \, kg$ of water.Given that the hardness is $50 \, ppm$,it means there are $50 \, mg$ of $MgSO_4$ per $10^6 \, mg$ of water.Therefore,in $1 \, kg$ of water,there are $50 \, mg$ of $MgSO_4$ present.Thus,the correct option is $B$.

The hardness of a water sample due to $MgSO_4$ is $50 \, ppm$. Calculate the amount of $MgSO_4$ in $mg$ present in $1 \, kg$ of water.

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