What is the major product obtained in the fol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction involves the nucleophilic substitution of a bromine atom by an ammonia $(NH_3)$ molecule. In the given molecule,there are two bromine

Vedclass · Accepted Answer

$2-$bromobenzylamine

Vedclass · Answer

(A) The reaction involves the nucleophilic substitution of a bromine atom by an ammonia $(NH_3)$ molecule. In the given molecule,there are two bromine atoms: one is a benzylic bromide $(-CH_2Br)$ and the other is an aryl bromide (attached directly to the benzene ring). The benzylic bromide is highly reactive towards nucleophilic substitution ($S_N2$ or $S_N1$ depending on conditions) because the resulting carbocation is resonance-stabilized or the transition state is easily formed. In contrast,the aryl bromide is very unreactive towards nucleophilic substitution due to the partial double bond character of the $C-Br$ bond caused by resonance with the benzene ring. Therefore,the $NH_3$ molecule will selectively attack the benzylic carbon,replacing the $-Br$ group with an $-NH_2$ group to form $2$-bromobenzylamine.

What is the major product obtained in the following reaction?

Similar Questions

The correct reactivity order of the following compounds towards alkaline hydrolysis is:-
$I. \ p-CH_3O-C_6H_4-CH_2Cl$
$II. \ C_6H_5-CH_2Cl$
$III. \ p-CH_3-C_6H_4-CH_2Cl$
$IV. \ m-CH_3-C_6H_4-CH_2Cl$

The increasing order of reduction of alkyl halides with zinc and dil. $HCl$ is:

The following reaction is a/an:
$CH_3-CH_2-CH_2-Br \xrightarrow{KOH} CH_3-CH=CH_2 + KBr + H_2O$

The most reactive molecules towards $SN^1$ reaction are:

Which of the following rules applies in the reaction:
$CH_3CHBrCH_2CH_3 \xrightarrow{alc. KOH}$
$(i)$ $CH_3CH = CHCH_3$ (major product)
$(ii)$ $CH_2 = CHCH_2CH_3$ (minor product)

Vedclass Test Series

Exam Paper Generator

Online Exam Module