The increasing order of reduction of alkyl halides with zinc and dil. $HCl$ is:
- A$R-Cl < R-I < R-Br$
- B$R-Cl < R-Br < R-I$
- C$R-I < R-Br < R-Cl$
- D$R-Br < R-I < R-Cl$
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Similar Questions
The product of the reaction between ethylbenzene and $N$-bromosuccinimide $(NBS)$ is:
DifficultAIEEE 2012
View SolutionMatch the following:
Column $I$ Column $II$ $A$. $CH_3-CHBr-CD_3$ on treatment with alc. $KOH$ gives $CH_2=CH-CD_3$ as a major product. $P$. $E1$ reaction $B$. $Ph-CHBr-CH_3$ reacts faster than $Ph-CHBr-CD_3$. $Q$. $E2$ reaction $C$. $Ph-CH_2-CH_2Br$ on treatment with $C_2H_5OD / C_2H_5O^-$ gives $Ph-CD=CH_2$ as the major product. $R$. $E1cb$ reaction $D$. $PhCH_2CH_2Br$ and $PhCD_2CH_2Br$ react with same rate. $S$. First order reaction
| Column $I$ | Column $II$ |
| $A$. $CH_3-CHBr-CD_3$ on treatment with alc. $KOH$ gives $CH_2=CH-CD_3$ as a major product. | $P$. $E1$ reaction |
| $B$. $Ph-CHBr-CH_3$ reacts faster than $Ph-CHBr-CD_3$. | $Q$. $E2$ reaction |
| $C$. $Ph-CH_2-CH_2Br$ on treatment with $C_2H_5OD / C_2H_5O^-$ gives $Ph-CD=CH_2$ as the major product. | $R$. $E1cb$ reaction |
| $D$. $PhCH_2CH_2Br$ and $PhCD_2CH_2Br$ react with same rate. | $S$. First order reaction |
The increasing rate of $S_N1$ reaction in the following compounds is:
DifficultJEE MAIN 2019
View SolutionConsider the following groups:
$I$. $-OAc$
$II$. $-OMe$
$III$. $-OSO_2Me$
$IV$. $-OSO_2CF_3$
The order of leaving power is:
$I$. $-OAc$
$II$. $-OMe$
$III$. $-OSO_2Me$
$IV$. $-OSO_2CF_3$
The order of leaving power is:
Difficult
View SolutionThe reaction $CH_3-CH(C_6H_5)-CH(Br)-C_6H_5 \xrightarrow{alc.KOH} A$. Identify the product $A$.
Difficult
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