What is the major alkene formed in the follow | vedclass

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(D) Hofmann elimination of quaternary ammonium salts follows the anti-Zaitsev rule,where the least substituted alkene is formed as the major product d

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(D) Hofmann elimination of quaternary ammonium salts follows the anti-Zaitsev rule,where the least substituted alkene is formed as the major product due to steric hindrance.In the given molecule,the nitrogen atom is attached to three different types of $\beta$-hydrogens:$1$. The $\beta$-hydrogens on the methyl groups attached to the nitrogen.$2$. The $\beta$-hydrogen at the $C-2$ position of the ring.$3$. The $\beta$-hydrogen at the $C-6$ position of the ring.Elimination involving the $C-2$ hydrogen leads to the formation of the less substituted alkene (terminal alkene) because the base abstracts the most accessible proton,which is less sterically hindered. Thus,the major product is the one where the double bond is formed at the terminal position relative to the ring,resulting in the formation of $N,N$-dimethylpent$-4-$en$-2-$amine.

What is the major alkene formed in the following Hofmann elimination?

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