What is the kinetic energy (in $J \ mol^{-1}$) of one mole of an ideal gas (molar mass $= 0.1 \ kg \ mol^{-1}$) if its rms velocity is $4 \times 10^2 \ ms^{-1}$ at $T(K)$?

  • A
    $2 \times 10^5$
  • B
    $8 \times 10^4$
  • C
    $8 \times 10^2$
  • D
    $8 \times 10^3$

Explore More

Similar Questions

What is the relationship between the most probable speed $(\alpha)$,average speed $(v)$,and root mean square speed $(u)$?

Explain the following terms:
$(i) u_{mp}$
$(ii) u_{av}$
$(iii) \overline{u}^2$
$(iv) u_{rms}$

Difficult
View Solution

For a gaseous state,if the most probable speed is denoted by $C^*$,average speed by $\overline{C}$,and root mean square speed by $C$,then for a large number of molecules,the ratio of these speeds is:

If the kinetic energy and $RMS$ speed of a gas at a certain temperature are $4.0 \ kJ \ mol^{-1}$ and $5.0 \times 10^4 \ cm \ s^{-1}$,respectively,the molecular weight of the gas is:

One way to decrease the average speed of molecules of an ideal gas is ............. .

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo