For a gaseous state,if the most probable spee | vedclass

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Question

(C) The expressions for the speeds are: Most probable speed $(C^*)$ = $\sqrt{\frac{2RT}{M}}$ Average speed $(\overline{C})$ = $\sqrt{\frac{8RT}{\pi M}

Vedclass · Accepted Answer

$C^* : \overline{C} : C = 1 : 1.128 : 1.225$

Vedclass · Answer

(C) The expressions for the speeds are: Most probable speed $(C^*)$ = $\sqrt{\frac{2RT}{M}}$ Average speed $(\overline{C})$ = $\sqrt{\frac{8RT}{\pi M}}$ Root mean square speed $(C)$ = $\sqrt{\frac{3RT}{M}}$ The ratio is $C^* : \overline{C} : C = \sqrt{2} : \sqrt{\frac{8}{\pi}} : \sqrt{3}$. Dividing by $\sqrt{2} \approx 1.414$: $1 : \sqrt{\frac{4}{\pi}} : \sqrt{1.5} \approx 1 : 1.128 : 1.225$.

For a gaseous state,if the most probable speed is denoted by $C^*$,average speed by $\overline{C}$,and root mean square speed by $C$,then for a large number of molecules,the ratio of these speeds is:

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