What is the decreasing order of stability (mo | vedclass

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(B) The stability of carbocations is determined by the number of $\alpha$-hydrogens (hyperconjugation) and inductive effects. $1$. Carbocation $3$ is

Vedclass · Accepted Answer

$3 > 2 > 5 > 4 > 1$

Vedclass · Answer

(B) The stability of carbocations is determined by the number of $\alpha$-hydrogens (hyperconjugation) and inductive effects. $1$. Carbocation $3$ is a tertiary carbocation with $9 \alpha$-hydrogens,making it the most stable. $2$. Carbocation $2$ is a secondary carbocation with $6 \alpha$-hydrogens. $3$. Carbocation $5$ is a secondary carbocation with $4 \alpha$-hydrogens. $4$. Carbocation $4$ is a primary carbocation with $2 \alpha$-hydrogens and an additional $+I$ effect from the methyl group. $5$. Carbocation $1$ is a primary carbocation with $2 \alpha$-hydrogens. Comparing these,the order is $3 > 2 > 5 > 4 > 1$.

List-$I$ (Carbocation)	List-$II$ (Type)
$A$. $CH_3-C^{+}(CH_3)-CH_3$	$I$. Secondary carbocation
$B$. $CH_3-C^{+}H-CH_3$	$II$. Methyl carbocation
$C$. $CH_3-CH_2^+$	$III$. Primary carbocation
$D$. $CH_3^+$	$IV$. Tertiary carbocation

What is the decreasing order of stability (most stable $\to$ least stable) of the following carbocations?

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The increasing order of basicity for the following intermediates is (from weak to strong):
$(i)$ $(CH_3)_3C^{-}$
$(ii)$ $H_2C=CH-CH_2^{-}$
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$(iv)$ $CH_3^{-}$
$(v)$ $CN^{-}$

Match the following columns and select the correct option.

List-$I$ (Carbocation) List-$II$ (Type)

$A$. $CH_3-C^{+}(CH_3)-CH_3$ $I$. Secondary carbocation

$B$. $CH_3-C^{+}H-CH_3$ $II$. Methyl carbocation

$C$. $CH_3-CH_2^+$ $III$. Primary carbocation

$D$. $CH_3^+$ $IV$. Tertiary carbocation

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